Evaluate the limit below. lim ( 4 + h ) 2 - 16 h - 0 h SOLUTION If we define F (h ) = (4+ h ) 2 - 16 h then we can't compute the lim F(h) by letting h = 0, because F(0) is undefined. But if we simplify F(h) algebraically, we find the following. h - 0 + 8h + 16 - 16 F(h) = h = h (Recall that we consider only h # 0 when letting h approach 0.) Thus, we get the following. lim (4 + h) 2 - 16 _ lim h - 0 h h - 0