Evaluate the limit limx$02$ex$-23$x using L$\text{'}$H$$pital$\text{'}$s rule.

After applying L$\text{'}$H$$pital$\text{'}$s rule, the limit becomes $($fill in a function$)$:

limx$0$ $$\backslash$frac$\{2\}\{3\}$$$23$Incorrect$2$ex$3$

So the answer is $($fill in a number$)$:

limx$02$ex$-23$x$=23$Correct $$