Evaluate the limit using the substitution $=12x.$

$\underset{x0}{lim}\frac{sin12x}{x}$

Consider the following approach to determine if the limit exists.

Let $=12x.$ Then $0$ as $x0$ and $x=\frac{}{12}.$ Hence,

Step $1$: $\underset{x0}{lim}\frac{sin12x}{x}=\underset{0}{lim}\frac{sin}{\frac{}{12}}$

Step $2$: $=12\underset{0}{lim}\frac{sin}{}$

Step $3$: $=12(0)$

Step $4$: $=0$

Therefore, $\underset{x0}{lim}\frac{sin12x}{x}=0.$

Is this limit correct? If not, identify the step where an error first occurs.

No errors are present.

Step $4$

Step $1$

Step $2$

Step $3$Find the correct value of the given limit$.$

$\underset{x0}{lim}\frac{sin12x}{x}=$