Evaluate the line integral along the given path. *2 + 12+ 22 ds C: r(t) = sin(t)i + cos(t)j + 5k Osts 3Given : ( ( x 2 + 4 2 + 2 2 ) ds Co a ( t ) = since) ; + cos ( t ) j + 5k - (lil Remember that 12 df 00 0 (Ill ) From equation ciis 2 ( t ) = sin ( t ) + + cosctij + 5k X 4 Z x = sint, cost ft y = cost, dy - - sint olf Z = 5 , dz = 0 civ) putting value from egeivs into eq(ill) ds = JE sint ) 2 + (cost ) 2 +or at = sin2t + cosat de sim 20 + cos 2 0 = 1 ds = 1 de- ds = at ( x )