Example 1: A 40 @ solenoid with a cross sectional area of 8@ is wound with 300 turns of wire and made to carry a current of 1.2. Its core has a relative permeability of 600. Calculate the flux of the solenoid. Solution: The 40 @ @ solenoid generates a magnetic field in vacuum and is computed as follows: Where ) (300 0.4070 ~1.13 X 10-340 Consider that the core has value of 600. Thus, we have: " =0......040.= (600) (1.13 x 10-3..) ~ 0.680 Note that because the field lines are perpendicular to the cross section of the solenoid, the magnetic flux is computed as follows: 1292 = 1000 712