Question: EXAMPLE 2 A simply supported beam has an effective span of 8 m and supports characteristic dead ( g k ) and live ( q

EXAMPLE 2
A simply supported beam has an effective span of 8m and supports characteristic dead (gk) and live (qk) loads of 15kNm-1 and 10kNm-1 respectively. Determine suitable dimensions for the effective depth and width of the beam.
From Table 3.17, span/effective depth ratio for a simply supported beam is 12. Hence effective depth, d, is
d=span12=800012~~670mm
Total ultimate load =(1.4gk+1.6qk) span =(1.415+1.610)8=296kN
Design shear force (V)=2962=148kN and design shear force, v, is
v=Vbd=148103670b
Assuming v is equal to 1.2Nmm-2, this gives a beam width, b, of
b=Vdv=1481036701.2=185mm
Hence a beam of width 185mm and effective depth 670mm would be suitable to support the given design loads.
After designing the size of the beam, reinforce the beam and check for deflections
EXAMPLE 2 A simply supported beam has an

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