Example 4: The loads on the Parker truss shown in Fig. P-430, determine the forces in members BD, BE, CE, and DE. (combination of method of joints and method of sections) A 000 F H D B MATHalino I 135 kN 135 kN 135 kN 135 kN 135 kN 135 kN 135 kN 8 panels at 7.5 m = 60 m Figure P-430 1) FBD =645.3 kN (compression), FBE =287.4 kN (tension), FCE =437.5kN (compression), FDE =75.9 kN (compression) 2) FBD =645.3 kN (comp), FBE =287.4 kN (ten), FCE =0 KN, FDE =75.9 kN (comp) 3) FBD =645.3 kN (comp), FBE =287.4 kN (ten), FCE =437.5kN (ten), FDE =75.9 kN (comp) 4) FBD =645.3 kN (comp), FBE =287.4 kN (ten), FCE =437.5kN (ten), FDE =0 kN 13