Question: Example 6.3: Find the distance between two successive nodes in a stationary wave on a string vibrating with frequency 64 Hz. The velocity of progressive






Example 6.3: Find the distance between two successive nodes in a stationary wave on a string vibrating with frequency 64 Hz. The velocity of progressive wave that resulted in the stationary wave is 48 m s .Example 6.4: An air column is of length 17 cm long. Calculate the frequency of 5th overtone if the air column is (a) closed at one end and (b) open at both ends. (Velocity of sound in air = 340 ms-1).Example 6.5 : A closed pipe and an open pipe have the same length. Show that no mode of the closed pipe has the same wavelength as any mode of the open pipe
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