Example: Comparison between Normal & Oblique Shocks Objective: (a) to determine P2, T2, P12, As. Solution: Using M1.837, From normal shock table, we get (M=0.608; 2n normal shock table M Min M2n M2 P2/P1 T2/T1 1.83 0.60993 3.74038 1.55415 P2/P= 3.77 1.84/ 0.60780,' 13.78320 1.56173/ TT=1.567 Found Given Found - = Using M2 M2 sin(0 8) = M2 sin(38-(20)=0.608 We get M = 2.0; (P2)= (3.77)*100 = 377 kPa; (T2)= (1.559)*300 = 467.7K; Objective Week - CP7B: Find P2 [Mpa] #