Example Problem #2 Determine the total pressure drop in a section of 6" piping that runs as follows 180' horizontally Bends upward 90 Runs 20' vertically Bends north 90 Runs another 200' horizontally through a fully open gate valve The pressure drop is 0.0065 psi/foot. Look up Equivalent Length from the table Solution: Component Amount Length 180' + 20' + 200 400 ft 90" elbows 2 8.9 ft Fully open gate valve 1 3.2 ft Solve: Total length = (1)(400ft) + (2)(8.9ft) + (1)(3.2) = 421 ft Pressure drop = 0.0065 psi)(421 ft) = 27.4 psi After viewing the Power Point, determine the pressure drop in a section of 6" piping described below. Use the table from the PowerPoint pasted below for the equivalent lengths data. Upload your work after you solve the problem. . Be sure to show your work in the submission. Description of Piping follows here. 36' horizontally bends upward 90 goes 20' vertically bends north 90 runs another 114' horizontally through a fully open gate valve pressure drop is 0.0065 psi/foot. o o Equivalent Length Using the equivalent length, the pressure drop in a section of piping can be estimated. The pressure drop per foot of piping is required. By knowing the length of the piping and looking up the equivalent length of valves and fittings, the total pressure drop due to friction can be calculated. Fitting Detail Fitting Detail Equivalent Length 190 Equivalent Length 1.6 6" Globe Valve fully open 90 elbow 1" fully open 3.2 90 elbow 2" 3.1 6" Full port gate valve % open 4.4 open 5.9 8.9 6Full port 20 90 elbow 3" gate valve 6" Full port 100 90 elbow 4" gate valve 6" Full port y open 400 90 elbow 6 gate valve 6" Tee-line 3.8 900 elbow 8" 12' flow 6" Tee- 18 900 elbow 10" 14 branch flow Table from Textbook Fluid Mechanics, 2017. Section 5-9 Equivalent length, page 79