Question: Example: . Throughput time is the time it takes for a product to go through the production process with no waiting. The parallel stations have

Example: . Throughput time is the time it takes for a productExample:

. Throughput time is the time it takes for a product to go through the production process with no waiting. The parallel stations have no effect on throughput time.

The throughput time is

12+5+12=2929

minutes (enter your response as a whole number.)

Part 3

b. The process time of a station is the time to produce a given number of units (or a batch of units) at that workstation. Bottleneck time is the time of the longest process (the slowest workstation) in the system. Calculate the process time per unit for each station.

Part 4

The process time for station 1 of the new work

cell=66

minutes per unit (enter your response as a whole number.)

Part 5

The process time for station 2 of the new work

cell=55

minutes per unit (enter your response as a whole number.)

Part 6

The process time for station 3 of the new work

cell=66

minutes per unit (enter your response as a whole number.)

Part 7

Bottleneck time of a system is the time of the longest process (the slowest workstation) in the system.

The bottleneck time of the new work cell is

66

minutes per unit (enter your response as a whole number.)

Part 8

c. If the firm operates

8

hours per day, 6 days per week, what is the weekly capacity of the work cell with the second machine at workstation

3?

Part 9

First calculate the total work time available per week.

6

days/week8

hours/day60

minutes/hour=28802880

minutes/week (enter your response as a whole number.)

Part 10

Then divide the total work time available per week by the bottleneck time of the new work cell.

The capacity of this work

cell=2880 minutes/week6 minutes/unit=480480

units/week (enter your response as a whole number.)

Part 11

d. If the firm operates

8

hours per day, 6 days per week, what is the weekly capacity of the work cell without the second machine at workstation

3?

Part 12

Without the second machine, process time for station

3

is

1212

minutes per unit (enter your response as a whole number.)

Part 13

Thus, the bottleneck moves to station

3.

Divide the total work time available per week by the bottleneck time of this work cell.

The capacity of this work

cell=2880 minutes/week12 minutes/unit=enter your response here

units/week (enter your response as a whole number.)

The manager, Ms. Hartley, has asked you to evaluate the system if she adds a parallel machine at station 3. a) The throughput time of the new work cell is minutes (enter your response as a whole number)

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