Exercise 1: Designing the experiment Like in previous experiments, your task is to measure a parameter that may seem difficult to measure. The index of refraction describes the speed of light through a medium, but you won't be able to measure displacement over time like in Lab 1 (light is waaaaay faster than your camera's frame rate... unless you have this camera). Since you can't measure the speed of light in various media directly you will make measurements based on Snell's Law and determine the index of refraction indirectly. You will work out how to do this below. Snell's Law is a great equation; two sides. 4 variables, one sweet sweet principle. That means. in order to solve for the index of refraction ofnz, you need to know 9"": , E),ef , and n1. To get familiar with this great equation, consider the following chart of experimental data: 6m 9m sin(9im,) sin(9m) [deg] [deg] [11 [11 10 12.5 0.174 0.216 20 25.1 0.342 0.424 30 38.4 0.5 0.621 40 53.0 0.643 0.799 50 72.0 0.766 0.951 The experiment was set up exactly like the picture of Physics Girl spearfishing (light travels from the first material into a second material at angle Gina. and is refracted at an angle Bref as it travels through the second material) with one difference: the materials are not air and water, and their refractive indices are unknown. However. this data can be used to determine the ratio between the two material's refractive indices(n1ln2). In the next section. you will do exactly that. (1.1) i) Calculate Sin(9ref) and sin(&.m) for the values in the table above' and submit your table. ii) Referring to Snell's Law in your answer, which material do you think has the higher refractive index; the first material (incident angle), or the second material (refracted angle)? (2 marks) Given the table, we can tell that the angle of refraction is greater than the angle of incident because the refracted ray is bending away from the normal. The higher refractive index would be the 15t material