Exercise 1. The on-axis magnetic field due to a circular current loop of radius R lying flat in the my plane, centered at the origin, and carrying current i is given by Equation 1. We will take this formula for granted today and derive it ofcially next week. _ no .1an2 411' (R2+22)3/2 82 {1} Show that Equation 1 is equivalent to R3 32 = 30 (R2 + Zz)3/2 where B0 is the magnetic field at the center ofthe loop. Express B0 in terms of [.10 , R, and i. What is Bo for l=200A and R=U.1 m? Graph 32 as a function of z from z=-2R to z=2R (using the numerical values above} in Excel. Make it easy to vary the values off? and