Question: Exercise 14. Evaluate J V1 + x2 dr using the hyperbolic trigonometric substitution r = sinh(t). (sinh is defined in the rules for derivatives notes;

 Exercise 14. Evaluate J V1 + x2 dr using the hyperbolic

trigonometric substitution r = sinh(t). (sinh is defined in the "rules for

Exercise 14. Evaluate J V1 + x2 dr using the hyperbolic trigonometric substitution r = sinh(t). (sinh is defined in the "rules for derivatives" notes; it's (et - e-t) /2). Why would someone think of this? What is the antiderivative you wind up with

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