Question: Exercise 3 Show that, for | - - ? N ( FOL ) : | - - ? N A B , A A x

Exercise 3
Show that, for |--?N(FOL):
|--?NAB,AAx.A|--?NAAx.B
is admissible in N with no side conditions.
|--?NAAx.A|--?NAtx
is admissible for legal Atx.
This version of the deduction theorem and its inverse:
,A|--?NB|--?NAAAB,|--?NAAAB,A|--?NB
 Exercise 3 Show that, for |--?N(FOL): |--?NAB,AAx.A|--?NAAx.B is admissible in N

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