Question: ! Exercise 3.2.5: Show that if a relation has no attribute that is functionally determined by all the other attributes, then the relation has no

! Exercise 3.2.5: Show that if a relation has no attribute that is functionally determined by all the other attributes, then the relation has no nontrivial FD's at all
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
