Question: Exercise 5.7.4. Let f be an isometry and TAB a translation with vector AB. Show that foTABOf = Tf(A)f(B) (translation with vector f( A) f(

Exercise 5.7.4. Let f be an isometry and TAB a translation with vector AB. Show that foTABOf = Tf(A)f(B) (translation with vector f( A) f( B) ).Hints: fo(ror2)of 1=(forof )o(formof ]). forof = rf() ifr is a reflection and f is an isometry. You can also do it by use the classification of an isometry

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