Exercise $6-2$

$I_x=?,I_y=?$

I need your help with integration

$dA=ydx(0,2)Y^{2}dydy??oris$ itydx$(0,2)y^{2}drdy$

$(2-x)dA=(2-y)dy$

${\displaystyle \underset{0}{\overset{2}{}}}{y}^2(2-y)dy=\frac{2y^3}{3}-\frac{y^4}{4}$

$=\frac{16}{3}-\frac{16}{4}=\frac{16}{12}=$