? Exercise 9.4. 6 Recall from Example 9.4.2 that this Maclaurin series for m f(:B) = cos a: is Z (1) . To show that this 19:0 (212)! Maclaurin series converges to cos a: for all real numbers a: what is the smallest M you could use? Question Help: 8 Message instructor 0 Post to forum Submit Question Next Page This question has 4 parts! Answer each part correctly to get the next part. Looking at the series m2 m3 $4 $5 53 I I I I 61F$'2!'3!'41'5!F and the two series :02 x4 cos($):1+4! :33 m5 sm(:13)::c3!+i it looks like we may be able to combine cos(a) and sin($) to get em. How could that work? Recall the imaginary number i : V 1 . Plug iii: into em get a power series: em : co + 01$ + C2132 I 03303 + C4334 -l- with coefficients co no -o 1 '5 , 03 _E V 06 , C4- E V 0' Part2 of 4 2! . 3! 4! Now multiply 2' times the series for sin(a:) to get a power series: isin(:) : 01:3 + 031:3 I C5$5 + with coefficients CPD WI: \"~5sz Question Help: 8 Wost to forum