Exercise. Simplify the expression

$\frac{\frac{4}{x-2}+1}{\frac{x}{x+3}-\frac{4}{x-2}}.$

Show your work $as$ indicated below.

First, $we$ multiply the numerator and the denominator $by$ the lowest common denominator

and obtain that

Then $we$ simplify the numerator and the denominator.

$\frac{\frac{4}{x-2}+1}{\frac{x}{x+3}-\frac{4}{x-2}}=\frac{?x^2+,?x+}{?x^2+,?x+}.$