explain solution

3.112 A setup as in Fig. P3.108 has the R-410A initially at 1000 kPa, 50"C of mass 0.1 kg. The balancing equilibrium pressure is 400 kPa and it is now cooled so the volume is reduced to half the starting volume. Find the work and heat transfer for the process. P C.P. Take as CV the 0.1 kg of R-410A. Continuity Eq.: my = m = m ; 1000 Energy Eq.3.5 m(u2 - uj) = 1Q2- 1W2 2 400 + Process Eq.: P = Pfloat or v = C = VI State 1: (P, T) = v =0.0332 m3/kg. uj = 292.695 kJ/kg State 2: (P, v) = v2=v1/2 =0.0166 m3/kg