explain solution and how they got g(x,y,z) = y - (3-2x)

EX. Use Stokes' theorem to evaluate $ 23 d x + y? dy - x'dz , where C is " the carve of intersection of the cylinder "+231 and the plane 2xty = 3 , oriented counterclockwise as viewed from the right side of the y-axis . 2 2 xty = 3 2 xty = 3 31 C is the trace of the cylinder x2+ 2 2 1 in the plane 2xty = 3 . For Stokes' theorem we will use the part of 2xty = 3 inside ( S: 4 = 3-2x R = projector of S ( X, z ) ER out xz- plane R: DEX 2 + 2 2 =1 S : 9 (xyz ) =0 g ( my , 2 ) = 4 - ( 3-2x ) N = vg = vg(y-3+2x) =(2, 1, 0 ) T N points to the rough