Question: Explain the correct answer for each part to guarantee points Q3 (7 points, suggested time 13 minutes) VBX = UB 46 A toy car coasts

Explain the correct answer for each part to guarantee points

Explain the correct answer for each part to guarantee points Q3 (7

Q3 (7 points, suggested time 13 minutes) VBX = UB 46 A toy car coasts along the curved track shown above. The car has an initial speed VA when it is at point A at the top of the track, and the car leaves the track at point B with speed v: at an angle O above the horizontal. Assume that the energy loss due to friction is negligible. (a) Suppose the toy car is released from rest at point A (VA = 0). i. After the car leaves the track and reaches the highest point in its trajectory it will be at a different height than it was at point A. Briefly explain why this is so. The car will be at a different height because it is launched at an angle. Although Uqis converted to kinte, the angle would produce a different height than at point A. 1/2 ii. Determine the speed of the car when it is at the highest point in its trajectory after leaving the track, in terms of VB and 0 . Briefly explain how you arrived at your answer. Projectile motion Speed before launch; Agh = Love , 12 gh = VB) The speed of the car is the same Using conservation of energy the speed is equal to vagh. The velocity tays constant ony as no forces actonit ( VB = tcost (b) Suppose the toy car is given an initial push so that it has nonzero speed at point A. Determine the speed VA of the car at point A such that the highest point in its trajectory after leaving the track is the same as its height at point A. Express your answer in terms of VB and 0 . Explain how you arrived at your

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