Explain the enthalpic and entropic contributions of the total contribution in Gibbs free energy, for the reaction
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Explain the enthalpic and entropic contributions of the total contribution in Gibbs free energy, for the reaction process at B and C, shown in the figure below.
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AH= -TAS= -140 kJ/mol -82 k/mol AH= AG= -1326 kJ/mol +110 kJ/mol AG = -218 kJ/mol AH= -1367 kJ/mol -TAS = -136 KJ/mol AG= -30 kJ/mol -TAS=+41 kJ/mol (a) Fermentation of glucose to ethanol (b) Combustion of ethanol (c) Decomposition of nitrogen pentoxide CH206(s)→ 20,H,OH(1) + 200,(g) CH;OH(I) + 30,(g)200,(g) + 3H,O(0) NgOg(s) + 2NOz(g) + 1/20z(g) Enthalpy favors this reaction, but entropy opposes it We could call this an "enthalpy-driven" reaction If water vapor were the product, an entropy increase would favor the reaction Both enthalpy and entropy changes favor the reaction. This is a somewhat unusual chemical reaction in that it is "entropy-driven." The reaction actually absorbs heat but is tavored by the large entropy increase resulting from the formation of gaseous products as well. AH= -TAS= -140 kJ/mol -82 k/mol AH= AG= -1326 kJ/mol +110 kJ/mol AG = -218 kJ/mol AH= -1367 kJ/mol -TAS = -136 KJ/mol AG= -30 kJ/mol -TAS=+41 kJ/mol (a) Fermentation of glucose to ethanol (b) Combustion of ethanol (c) Decomposition of nitrogen pentoxide CH206(s)→ 20,H,OH(1) + 200,(g) CH;OH(I) + 30,(g)200,(g) + 3H,O(0) NgOg(s) + 2NOz(g) + 1/20z(g) Enthalpy favors this reaction, but entropy opposes it We could call this an "enthalpy-driven" reaction If water vapor were the product, an entropy increase would favor the reaction Both enthalpy and entropy changes favor the reaction. This is a somewhat unusual chemical reaction in that it is "entropy-driven." The reaction actually absorbs heat but is tavored by the large entropy increase resulting from the formation of gaseous products as well.
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As we can see for all types of reactions G is negative but to make G negative the ... View the full answer
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