EXPLAIN THE SOLUTION PLEASEA $2m$ layer of clay is normally consolidated, located $2m$ below the surface. After

laboratory testing, the clay has $C_c=0\mathrm{.}6$ and $C_s=C_r=0\mathrm{.}1($see the soil compression graph

below$).$ The dense sand layer has minimal volume change under the loading. After a

loading of $290$kPa is applied to the surface,

Calculate the final settlement:

$e_0=1\mathrm{.}5,h_0=2m,{}_0^{\text{'}}=3(20-10)=30$kPa,${}_1^{\text{'}}=30+290=320$kPa

$e=C_{c}lo{g}_{10}(\frac{{}_o^{\text{'}}}{{}_1^{\text{'}}})=0\mathrm{.}6lo{g}_{10}(\frac{30}{320})=-0\mathrm{.}6168$

Settlement of NC soil : $(1D$ consollidation$)$

$\frac{h}{h_o}=\frac{e}{1+e_o}=(\frac{-0\mathrm{.}6168}{1+1\mathrm{.}5})=-0\mathrm{.}2467$

$h_0=2000mm$

$h=-0\mathrm{.}1362000=-493mm$