Explain what is meant by the equation lim x 2 f(x) = 4. The values of f(x) can be made as close to 2 as we like by taking x sufficiently close to 4. If |x1 2| < |x2 2|, then |f(x1) 4| < |f(x2) 4|. The values of f(x) can be made as close to 4 as we like by taking x sufficiently close to 2. f(x) = 4 for all values of x. If |x1 2| < |x2 2|, then |f(x1) 4| |f(x2) 4|. Is it possible for this statement to be true and yet f(2) = 5? Explain. Yes, the graph could have a hole at (2, 4) and be defined such that f(2) = 5. Yes, the graph could have a vertical asymptote at x = 2 and be defined such that f(2) = 5. No, if f(2) = 5, then lim x2 f(x) = 5. No, if lim x2 f(x) = 4, then f(2) = 4