Question: Explain what the following code does and why it will not dequeue successfully char fnt 1(QueueNode headPtr, QueueNode tailPtr) if (* headPtr != NULL){ .

Explain what the following code does and why it will not

Explain what the following code does and why it will not dequeue successfully char fnt 1(QueueNode** headPtr, QueueNode** tailPtr) if (* headPtr != NULL){ . char value (*headPtr)->data QueueNode* tempPtr headPtr, headPtr = (* headPtr)->nextPtr; if (* headPtr == NULL) { tai|Ptr = NULL; free(tempPtr); return value; Else Printf("bla bla bl..."; (9 marks)

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Question: Explain what the following code does and why it will not dequeue successfully char fnt 1(QueueNode** headPtr, QueueNode** tailPtr) if (* headPtr != NULL){ .

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Question: Explain what the following code does and why it will not dequeue successfully char fnt 1(QueueNode headPtr, QueueNode tailPtr) if (* headPtr != NULL){ .