Question: Explain why, with big-O notation, the base of a logarithm can be ignored. In other words, explain why logan = O(login) for any integers a,

Explain why, with big-O notation, the base of a logarithm can

Explain why, with big-O notation, the base of a logarithm can be ignored. In other words, explain why logan = O(login) for any integers a, b, such that a > 0 and b > 0. Does similar logic allow us to ignore the base of an exponential function? (In other words, is it true that n3 is O(n^), for example?)

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