Explaination how did you get the answer please $??$In the circuit shown below, two $8-$bit shift register are put in shift right mode. Assume initially that:

RegA$=\frac{E}{16},$RegB$=4B_{16},$ Flip flop is set $($i$.$e$,Q=1),M=1.$

After applying $8$ clock cycles the decimal equivalent of RegA content as an $8-$bit signed $2\text{'}$s complement data is:

$52$

$31$

Ahaver is not listed

$84$

$172$