Question: EXPO(8 = 1 / [1,) services (note the notation change between my usual Exp and Arena's EXPO ), then we'd get w = 1/(0.125

 EXPO(8 = 1 / [1,) services (note the notation change between

my usual \"Exp" and Arena's \" EXPO \"), then we'd get w

EXPO(8 = 1 / [1,) services (note the notation change between my usual \"Exp" and Arena's \" EXPO \"), then we'd get w = 1/(0.125 0.1) = 40. Go ahead, see for yourself in Arena, but make sure that you run the system for 100,000 or so customers so that you can be sure that you're in steady-state! Finally, here's the GIGO question, which will show what can happen when you mis-model a component of your process: What is the (approximate) steady-state expected cycle time if you have i.i.d. UNIFCS, 15) interarrivals instead of EXPO(10 = 1/A) interarrivals? Note that both interarrival distributions have the same mean (10), but that doesn't necessarily imply that they'll have the same expected cycle times. Hint: You may want to use Arena as described above. \"la.about1 \"le.about10 \"V c.about23 '\"ld.about40 \"Tie.about62

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