F 13. An applied force acts on a 2kg mass as a function of the block's displacement from 0 as shown. The block starts from 1m/s at x = 0. Calculate the work done between: 0 & 1m, 1 & 2m, 2 & 4m and 0 and 6m. There is negative work(What do you think that is?). What is the mass' speed at 2, 4 and 6 meters? Hint: Area is the work!!!!!!!!!!!! !!!!!!!!! 12N 0 -10N Area = 12 m - 1/2mv, 2 14. Calculate the stopping point of the 10 kg block as it loses energy after each 12m 6m (F, here is 8N) pass. x(m) 10 (98) (12)=48x