Question: f: ( ) < < ( )~ + [ + ... ... ... ... ... . . () = 1 2 ( ) , =

\f: ( ) < < ( )~ + [ + ... ... ... ... ... . . () = 1 2 ( ) , = 1 ( ) ( )= = 1 2 ( ) , = = 1 = 0 = 1 , 1 2 < ( ) . < ( ) = 0, ( ) 1 1 = , ( ) = = = 2 2 2 , 2 = ( )~ => 2 2 (1) 2 + = (1) 2 (1) 2 ( ) [ [ (1) 0] + = ( )~ = [ + =2 (1) (1) => 2 = 1 2 2 + 1 3 3 1 4 4 + = 1 5 5 1 6 6 + 2 1 1 1 = 1 + + ............ 4 3 5 7 . 1 7 7

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