Question: f: 2 tan ( )= (1) 2 +1 ( ) 1 = 6 tan = 4 tan (1) = 3 tan 3 3 ( )

\f: 2 tan ( )= (1) 2 +1 ( ) 1 = 6 tan = 4 tan (1) = 3 tan 3 3 ( ) 3 = <5 3 1> 6 (1) 1 = 1 3 2 +1 (1) 1 = 0.52376745761 1 3 = 3.14260474566 ( ) (1) (1) 2 +1 (1) = <5 .

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