Question: The function, y(x), satisfying y' (x) = 3y(x) with y(0) = 1 is y(x) = e 3x y(x) = 3ex y(x) = e3x y(x)

The function, y(x), satisfying y' (x) = 3y(x) with y(0) = 1

is y(x) = e 3x y(x) = 3ex y(x) = e3x y(x)

The function, y(x), satisfying y' (x) = 3y(x) with y(0) = 1 is y(x) = e 3x y(x) = 3ex y(x) = e3x y(x) = e 3x y(x) 3ex y(x) 3ex

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