At least one ot tne answers a 2 of the questions remain unanswered Improper Integrals - Integrating over an infinite interval. In this problem our goal is to determine whether the improper integral below converges or diverges If it converges, we will determine the value of the improper integral I (X 3)2/3 Part I. We vill use the follcnhng definition: If f is continuous at every point of 81, bl except for the pointc in (a, b) and one or both one-sided limits of f at c are infinite, then we define Note: Ym can earn part's,' credit on this provided that both improper integrals on the right converge If either of the improper integrals on the right diverge then, the integral f(z) dx diverges For I < < 3, the area underthe curve = (z - 3)2/3 upon evaluating the definite integra] you found above, we have AZI Note: pur answer may contain rational exponents. Similarily, for 3 < < 7, the area under the curve u = Ar(t) - I to = t can be written as the definite integral from x = i to z 7 can be written as the definite integral 3)2/3 upon evaluating the definite integra] you found above, we have Note: pur answer may contain rational exponents. Part 2. Now we evaluate the limit of A1(t) and Ar(t) as 3 and as t 34 respectively lim A1 (t) Iirg AT(t) Note: pur answer may contain rational exponents. Part 3. Based on your answer for Part 2. abcme, the improper integral either converges to a finite value or diverges If the integral converges, state that it converges and to what value it converges Otherwise, state that it diverges to infinity The integral converse: to