Question: Ts = 2m b. 9.0 xlO C. d. (17 102 J) (1.7 x103J) (133)sin25.00 = (150)sin O g. 2.25x 108 mis 3.00 x 108

Ts = 2m b. 9.0 xlO C. d. (17 102 J) (1.7

x103J) (133)sin25.00 = (150)sin O g. 2.25x 108 mis 3.00 x 108

Ts = 2m b. 9.0 xlO C. d. (17 102 J) (1.7 x103J) (133)sin25.00 = (150)sin O g. 2.25x 108 mis 3.00 x 108 m/s 45 x 10 Q kg 2.0 x 103 kg/s2 K = J(66x 102 x 104 m/s)2 (0.32m)2

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