Question: F=(y-x)i+(z-y)j + (z-x)k; D: the region cut from the solid cylinder 2 + by the planes and z=3. Answer: -12pi

F=(y-x)i+(z-y)j + (z-x)k; D: the region cut from the solid cylinder 2

+ by the planes and z=3. Answer: -12pi

F=(y-x)i+(z-y)j + (z-x)k; D: the region cut from the solid cylinder 2 + by the planes and z=3. Answer: -12pi

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