F

$=,=A^{\text{'}}BD+A^{\text{'}}{B}^{\text{'}}{C}^{\text{'}}+A^{\text{'}}CD+BCD+B{C}^{\text{'}}{C}^{\text{'}}$

$=,(\frac{?}{\text{b}\text{a}\text{r}}(A)\frac{+}{b}ar(C))(BD\frac{+}{b}ar\frac{B}{b}ar(C)),+C^{\text{'}}D$

$=\frac{,}{b}ar(A)BD\frac{+}{b}ar\frac{A}{b}ar(B)\frac{*}{b}ar(C)\frac{+}{b}ar(C)*BD\frac{+}{b}ar(C)\frac{*}{b}ar(C)\frac{*}{b}ar(B),=A^{\text{'}}BD+B^{\text{'}}{C}^{\text{'}}(1+A^{\text{'}})+C^{\text{'}}D(1+A^{\text{'}}+B)$

$,-A^{\text{'}}BD+B^{\text{'}}{C}^{\text{'}}+C^{\text{'}}D\frac{?}{{?}_1}=+S$

$+C^{\text{'}}D$

Num

Question $7($L$.$O$\mathrm{.}4)(1\mathrm{.}0$pts$.)$: Basic Logic Gates $=A^{\text{'}}BD+B^{\text{'}}{C}^{\text{'}}+C^{\text{'}}D=L1+S$

Given the logic circuit below.

$\frac{?}{\text{b}\text{a}\text{r}}(C)B\frac{+}{b}ar(C).D(B\frac{+}{b}ar\frac{B}{b}ar(C))+\frac{C}{b}ar(C)=DB\frac{+}{b}ar\frac{B}{b}ar(C)$

$\frac{x^1}{b}ar(A+B)$

$(0\mathrm{.}5$

$\backslash$table$[[A,B,C,F$