$($f$)$ Assume that the particles generated upon failure are all cubes with the same dimensions. There are $N$ of these particles and the side length of the cube is $x.$ Using the values dervived in Q$2($c$)$ and $($e$)$ develop two equations in terms of $N$ and $x.$ From those equations calculate the length of one side of each cube and the number of cubes generated upon failure.

Side length of cube $(x)$

Enter numbers only, no formulas, units or scientific notation

Please note : my value for c $($volume change$)$ was $1\mathrm{.}19*10^-8$ m$^3,$ and my value for e $($ surface area formed$)$ was $4\mathrm{.}0783$ m$^2$