Question: F > - k x Name: q , behavior of two springs from different companies. K = F force Force vs compressed distance for Company

F>-kx
Name: q, behavior of two springs from different companies. K=F force Force vs compressed distance for Company A
Find the spring K=Fx
Force vs compressed distance for Company A
and R Snringr constant (in N/m) for
a. Company A Distancuod
Spring
~~1416=0.87Nm
q,
q,
b. Company B
~~916=0.56Nm
Force ispratement
11. If a marble is pressed against Company A's spring when it is compressed by 10 mm , how much kinetic energy would the marble receive when the spring is released?
KE=12mv2
F > - k x Name: q , behavior of two springs from

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