Question: f R e A 2 = [ ( 3 . 4 4 L + 2 ) 2 + ( 1 2 2 ( 1 +

fReA2=[(3.44L+2)2+(122(1+[1-1925tanh(2)]))2]12
Starting with this equation, and noting that when the flow becomes developed the contribution of the developing and developed terms are equal, derive the following expression for hydrodynamic entrance length
Lh+=0.0822(1+)2[1-1925tanh(2)]2
I can't plug it in right but it should be 193epsilon above too like in the first equation.
f R e A 2 = [ ( 3 . 4 4 L + 2 ) 2 + ( 1 2 2 ( 1 +

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