$f(x)=4x^2-e^x-e^{-x}$

Use the tolerance $={10}^{-5}$ and display the approximation using the long format. Print your calculation like the following table:

$\backslash$table$[[$step$,x,f(x),|x_{n+1}-x_n|$

$($c$)$ Using Newton's method with initial value $x_0=3$ and $x_0=5.$ To which root will the method converge?

please use octave