Question: f ( x ) = { a e x + b x , x 0 m , x = 0 e - 1 x 2

f(x)={aex+bx,x0m,x=0e-1x2+x+53,x>0
Determine the value of a,b, and m, assuming that the function f(x) is differentiable everywhere. Value of a=,b=, and m=
f ( x ) = { a e x + b x , x < 0 m , x = 0 e - 1 x

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