$F_y^D=$ Concentrated force acting on both handles as shown in the figure $($Magnitude is $281$bf$)$

Treat each handle sides as a straight rod of tapered rectangular cross$-$section of width ${0\mathrm{.}5}^{\text{'}\text{'}}$ at

the junction A and ${0\mathrm{.}1}^{\text{'}}$ near the end $D$

Out$-$of$-$plane thickness of each link to be ${0\mathrm{.}1}^{**}$

Ignore the slight bend midway along the handle

The plier jaw is oriented at $130$ to $y-$axis

Simplifying assumptions you are allowed to consider:

Segment DA is parallel to $x-$axis

Point $A$ is located at the mid$-$point of the $0\mathrm{.}5$ local width of the link

AG is $130$ to $y-$axis

Do the following for the link DAG:

Draw the Free Body Diagram of the link

Obtain the following forces and moments:

Compute $F_x^D,F_y^D,F_z^D,M_x^D,M_y^D,M_z^D$

Compute $F_x^A,F_y^A,F_z^A,M_x^A,M_y^A,M_z^A$

Compute $F_x^G,F_y^G,F_z^G,M_x^G,M_y^G,M_z^G$

Find the location where bending moment is highest

Find the location where the torsional moment is highest

Find the location where the stresses are highest

Find factor of safety at that point assuming yield strength to be $87$ kpsi

Draw a $3$D stress element $($cube$)$ showing the state of stress that point

Compute absolute maximum shear stress

Assuming Tresca or maximum shear stress as the failure criteria, compute the safety

factor

NOTE: All locations must be identified in coordinates by assuming origin of the coordinate system

at a suitable location. Consider $130$ degrees as theta and put together the equations. Assume AG

parallel to handle and ask yourself what components of forces will be at A$.$ Now repeat that assessment

with AG perpendicular to the handle.