Question: f2. f (x ) = = 1 27 (x5 + 2x3) Find (f-1)' (-11). f- 1 - f 27 (x5 + 2x3 ) = X

$\f2. f (x ) = = 1 27 (x5 + 2x3)$ Find (f-1)' (-11). f- 1 - f 27 (x5 + 2x3 ) = X = f'd (f-1)'(-11) =3. f(x) = sin x EXS Find (f-1)' (13). f- 1 V3 V3 2 sin x = V3 2 $X = fil ( F - 1 ) ' ( =\f7. Let$

\f2. f (x ) = = 1 27 (x5 + 2x3) Find (f-1)' (-11). f- 1 - f 27 (x5 + 2x3 ) = X = f'd (f-1)'(-11) =3. f(x) = sin x EXS Find (f-1)' (13). f- 1 V3 V3 2 sin x = V3 2 X = fil ( F - 1 ) ' ( =\f7. Let f (x) = x3 +x. g(x) = f-1(x) and g(2) = 1 g'(2) = 8. If f (4) = 5 and f'(4) = WIN then (f-1)'(5) = 9. Use the table of values to find (f-1)'(3). (f - 1)' (3) = X f f' 0 2 1 1 3 2 2 5 3 3 10 4

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