Question: f5. Solve for the unknown: tan2 3x + 2 tan 3x + 1 =0 for - NIN NIN* given => tam 2 3x + 2

\f5. Solve for the unknown: tan2 3x + 2 tan 3x + 1 =0 for - NIN NIN* given => tam 2 3x + 2 tam 32 + 1 = 0 for, - F SXCA = ) Jet, tam32 = d. SoI d2 + 2 d + 1 = 0 ( d + 1 ) d+1 = 0 or d+ 1 = 0 SoI d = -1 ,- 1 NOW, tam (32) = - 1 =d 32 = tom (- 1 ) 3X = 3 / A + In 3 In So, De = - I - 5x 12 123 given = 8 in ( 2x ) = 2 CSC( 2x ) - tom ( 2 ) 1 - Cas ( 2 2) .: we know. Sin (2x) = 28inx Ces x Ca8 (220) = Cas2 x- strife = 1-28th2x Jet, Lo Hos -> - 2 Cosa Sthe 2 8the - COSx = cot (2) -(I) NOW - ROH. S - 3 2 CSC ( 274 ) - tom (x ) " sinzx = 2) 2 [senzx ) cosa casksthe cast ( singat cos x ) - size = Gotoy -[II) san ( 2 ) by - ( I) & (IF) LOHS = ROHS

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