fast solution

Consider the software output: Paired T-Test and Cl: X1, X2 Paired T for X1 - X2 N Mean St Dev SE Mean XI 12 74.2430 1.8603 0.5370 X2 12 73.4797 1.9040 0.5496 Difference 12 2 2. 905560 0. 838763 954 CI for mean difference: (-1. 082805, 2. 609404) I-Test of mean difference = 0 (vs not = 0) : I-Value = _2 P-Value = ? (a) Fill in the missing values, including a bound on the p-value. (b) Can the null hypothesis be rejected at the a = 0.05 level? Why? (c) Is this a one-sided or a two-sided test? (d) Use the output and the t table to find a 99% two-sided confidence interval on the difference in means. (e) How can you tell that there is insufficient evidence to reject the null hypothesis just by looking at the (incomplete) software output and not making any additional computations