Question: FcLc = 2 X FDLD + 0.09 mm) ACEC ADED Lo= 300 mm, Ac= 600 mm-, Ec= 200 GPa; LD= 150 mm, Ap= 2500 mm

FcLc = 2 X FDLD + 0.09 mm) ACEC ADED Lo= 300 mm, Ac= 600 mm-, Ec= 200 GPa; LD= 150 mm, Ap= 2500 mm , ED= 101 GPa With P = 50 N, solving Equations 1 and 2 simultaneously yields [1 mark] Fc = 110 kN ans. FD = 80 kN ans

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