Question: FD 2 0 : S 0 3 + H 2 O Mst = 8 0 g / mol Mw = 1 8 g / mol

FD20
: S03+ H2O Mst=80 g/mol Mw=18 g/mol H2SO4 Msa=98 g/mol Xst =0.65 a)80 H-1

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