Question: Feed = 1 0 0 0 k g ; A benzene ) = ( 7 8 nitrobenzenc ( M M 1 1 2 3 )

Feed =1000kg;A benzene )=(78 nitrobenzenc (MM1123).xF=0.5=> mol. wt of feed =(0.5)(78)+(0.5)(123)=100.5.
Moles of beed, F=1000100.5=9.95kmol.
Residue in the still =k kmol, mole fraction of beuzene =x; mass of residue =W[78x+123(1-x)]=500=>W=500?.
Use Eq ?1(7.516), put the values of F,xF and )=(7.0.
Solvig, x=0.141,W=4.286. Use Eq 7.52 formatesial balance (9.95)(0.5)=(5.664)yD,av+(4.286)(0.141)=>(0.7),yD,av=0.77
The repossed concentration of benzene iu iu the accumulated condensate is not accirate.
 Feed =1000kg;A benzene )=(78 nitrobenzenc (MM1123).xF=0.5=> mol. wt of feed =(0.5)(78)+(0.5)(123)=100.5.

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